基本信息
源码名称:C# 简单推箱子游戏源码
源码大小:0.01M
文件格式:.cs
开发语言:C#
更新时间:2015-06-12
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   源码介绍



using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ConsoleApplication1
{
    class Program
    {
        private static void ditu(int[, ,] dt, int i)
        {
            for (int j = 0; j < 10; j  )
            {
                for (int k = 0; k < 10; k  )
                {
                    if (dt[i, j, k] == 0)
                    {
                        Console.Write("  ");
                    }
                    else if (dt[i, j, k] == 1)
                    {
                        Console.Write("■");
                    }
                    else if (dt[i, j, k] == 2)
                    {
                        Console.Write("□");
                    }
                    else if (dt[i, j, k] == 3)
                    {
                        Console.Write("★");
                    }
                    else if (dt[i, j, k] == 4)
                    {
                        Console.Write("♀");
                    }
                }
                Console.Write("\n");
            }
        }
        static void Main(string[] args)
        {
             int x = 1, y = 1, i = 0;
            int[, ,] dt = new int[3, 10, 10]  //定义一个二维数组用于接收地图
                {
                   { 
                     {1,1,1,1,1,1,1,1,1,1},
                     {1,4,0,1,0,0,0,0,0,1},
                     {1,0,0,0,0,0,2,0,3,1},
                     {1,0,1,1,0,1,0,0,0,1},
                     {1,0,0,0,0,0,0,0,0,1},
                     {1,3,1,1,1,1,1,2,1,1},
                     {1,2,1,0,0,0,0,0,0,1},
                     {1,0,0,0,0,1,1,0,0,1},
                     {1,1,0,1,0,0,0,3,0,1},
                     {1,1,1,1,1,1,1,1,1,1},
                   },
                   { 
                     {1,1,1,1,1,1,1,1,1,1},
                     {1,1,1,1,4,0,1,0,3,1},
                     {1,1,1,3,0,0,2,0,0,1},
                     {1,1,0,0,2,0,1,0,0,1},
                     {1,0,0,0,1,1,1,0,0,1},
                     {1,0,1,1,0,0,0,0,0,1},
                     {1,0,0,0,0,2,0,0,1,1},
                     {1,0,3,0,0,0,1,1,1,1},
                     {1,0,0,0,0,1,1,1,1,1},
                     {1,1,1,1,1,1,1,1,1,1},
                   },
                   { 
                      {1,1,1,1,1,1,1,1,1,1},
                      {1,1,0,0,4,0,0,3,1,1},
                      {1,1,0,2,0,0,0,2,3,1},
                      {1,1,0,0,2,1,1,0,0,1},
                      {1,1,0,1,0,0,0,3,0,1},
                      {1,0,3,0,0,0,1,0,1,1},
                      {1,0,0,1,1,2,0,0,1,1},
                      {1,3,2,0,0,0,2,0,1,1},
                      {1,1,3,0,0,0,0,0,1,1},
                      {1,1,1,1,1,1,1,1,1,1},

                  } 
                };
            try
            {
                int count = 0;//临时变量
                int xzs = 0;//箱子数
                for (int j = 0; j < 10; j  )
                {
                    for (int k = 0; k < 10; k  )
                    {
                        if (dt[i, j, k] == 3)
                        {
                            xzs  ;
                        }
                    }
                }
                while (true)
                {
                    int temp = 0;
                    ConsoleKeyInfo s = Console.ReadKey();  //s用于接收用户输入的键
                    if (s.Key.ToString() == "DownArrow")
                    {
                        if (dt[i, x   1, y]!=1)
                        {
                            
                       
                        if (dt[i, x   1, y] == 0)//如果小人的下一步是0(空格),则两个元素交换  (下同)
                        {
                            temp = dt[i, x, y];
                            dt[i, x, y] = dt[i, x   1, y];
                            dt[i, x   1, y] = temp;
                            x  ;
                        }
                        else if (dt[i, x   1, y] == 2 && dt[i, x   2, y] == 0)//如果小人的下一步是箱子,箱子的下一步是空格,则三个元素进行交换 (下同)
                        {
                            temp = dt[i, x   2, y];
                            dt[i, x   2, y] = dt[i, x   1, y];
                            dt[i, x   1, y] = temp;
                            temp = dt[i, x   1, y];
                            dt[i, x   1, y] = dt[i, x, y];
                            dt[i, x, y] = temp;
                            x  ;
                        }
                        else if (dt[i, x   2, y] == 3 && dt[i, x   1, y] == 2) //如果小人的下面第二个元素是“★”
                        {
                            dt[i, x   2, y] = 2;//让五角星变成箱子
                            dt[i, x   1, y] = 4;// 让箱子变成小人
                            dt[i, x, y] = 0;    //让小人变成空格
                            x  ;
                            count  ;  //给临时变量赋值作为跳出循环的条件,当count等于xzs时跳出循环
                        }
                        }
                    }
                    else if (s.Key.ToString() == "UpArrow")
                    {
                        if (dt[i, x - 1, y] != 1)
                        {
                            if (dt[i, x - 1, y] == 0)
                            {
                                temp = dt[i, x - 1, y];
                                dt[i, x - 1, y] = dt[i, x, y];
                                dt[i, x, y] = temp;
                                x--;
                            }
                            else if (dt[i, x - 1, y] == 2 && dt[i, x - 2, y] == 0)
                            {
                                temp = dt[i, x - 2, y];
                                dt[i, x - 2, y] = dt[i, x - 1, y];
                                dt[i, x - 1, y] = temp;
                                temp = dt[i, x, y];
                                dt[i, x, y] = dt[i, x - 1, y];
                                dt[i, x - 1, y] = temp;
                                x--;
                            }
                            else if (dt[i, x - 2, y] == 3 && dt[i, x - 1, y] == 2) //如果小人的下面第二个元素是“★”
                            {
                                dt[i, x - 2, y] = 2; //让五角星变成箱子
                                dt[i, x - 1, y] = 4;// 让箱子变成小人
                                dt[i, x, y] = 0;    //让小人变成空格
                                x--;
                                count  ;  //给临时变量赋值作为跳出循环的条件,当count等于xzs时跳出循环
                            }
                        }
                    }
                     else if (s.Key.ToString() == "LeftArrow")
                    {
                        if (dt[i, x, y - 1] != 1)
                        {
                            if (dt[i, x, y - 1] == 0)
                            {
                                temp = dt[i, x, y - 1];
                                dt[i, x, y - 1] = dt[i, x, y];
                                dt[i, x, y] = temp;
                                y--;
                            }
                            else if (dt[i, x, y - 1] == 2 && dt[i, x, y - 2] == 0)
                            {
                                temp = dt[i, x, y - 2];
                                dt[i, x, y - 2] = dt[i, x, y - 1];
                                dt[i, x, y - 1] = temp;
                                temp = dt[i, x, y];
                                dt[i, x, y] = dt[i, x, y - 1];
                                dt[i, x, y - 1] = temp;
                                y--;
                            }
                            else if (dt[i, x, y - 2] == 3 && dt[i, x, y - 1] == 2) //如果小人的下面第二个元素是“★”
                            {
                                dt[i, x, y - 2] = 2; //让五角星变成箱子
                                dt[i, x, y - 1] = 4;// 让箱子变成小人
                                dt[i, x, y] = 0;    //让小人变成空格
                                y--;
                                count  ;  //给临时变量赋值作为跳出循环的条件,当count等于xzs时跳出循环
                            }
                        }
                    }
                    else if (s.Key.ToString() == "RightArrow")
                    {
                        if (dt[i, x, y   1] != 1)
                        {
                            if (dt[i, x, y   1] == 0)
                            {
                                temp = dt[i, x, y   1];
                                dt[i, x, y   1] = dt[i, x, y];
                                dt[i, x, y] = temp;
                                y  ;
                            }
                            else if (dt[i, x, y   1] == 2 && dt[i, x, y   2] == 0)
                            {
                                temp = dt[i, x, y   2];
                                dt[i, x, y   2] = dt[i, x, y   1];
                                dt[i, x, y   1] = temp;
                                temp = dt[i, x, y   1];
                                dt[i, x, y   1] = dt[i, x, y];
                                dt[i, x, y] = temp;
                                y  ;
                            }
                            else if (dt[i, x, y   2] == 3 && dt[i, x, y   1] == 2) //如果小人的下面第二个元素是“★”
                            {
                                dt[i, x, y   2] = 2; //让五角星变成箱子
                                dt[i, x, y   1] = 4;// 让箱子变成小人
                                dt[i, x, y] = 0;    //让小人变成空格
                                y  ;
                                count  ; //给临时变量赋值作为跳出循环的条件,当count等于xzs时跳出循环
                            }
                        }
                    }
                    else
                    {

                    }
                    Console.Clear();  //清屏
                    
                    ditu(dt, i);// 调用ditu函数打印地图
                    if (count==xzs)
                    {
                        Console.WriteLine("恭喜你过关了!");
                        Console.WriteLine("按任意键进入下一关!");
                        Console.ReadKey();
                        x = 1; y = 4;//初始化小人的位置
                        i  ;
                        count = 0;
                        xzs = 0;
                        for (int j = 0; j < 10; j  )
                        {
                            for (int k = 0; k < 10; k  )
                            {

                                if (dt[i, j, k] == 3)
                                {
                                    xzs  ;
                                }

                            }
                        }
                    }
                }
            }
            catch (Exception)
            {
               // Console.WriteLine("恭喜你全部过关了!");
                Console.ReadKey();
            }

          }
      }
    }